Math, asked by venushree, 1 year ago

a (2a – 3b) + ( a +b) ( 3b +7a) +9 ( b2 – a2)

Answers

Answered by realsujaykumar
2
= 2a^2 -3ab+3ab +7a^2+3b^2+7ab+9b^2 -9a^2
=7ab+ 12b^2
= b (7a +12b)
Answered by misscutie94
14

Answer:

Question :-

➠ a(2a - 3b) + (a + b) (3b + 7a) + 9(b² - a²)

Answer :-

➠ a(2a - 3b) + (a + b) (3b + 7a) + 9(b² - a²)

➻ 2a² - 3ab + a(3b + 7a) + b(3b + 7a) + 9b² - 9a²

➻ 2a² - 3ab + 3ab + 7a² + 3b² + 7ab + 9b² - 9a²

➻ 2a² + 7a² - 9a² + 3b² + 9b² + 7ab + 3ab - 3ab

➻ 9a² - 9a² + 12b² + 10ab - 3ab

➻ 12b² + 7ab

➻ b(12b + 7a)

∴ The value of a(2a - 3b) + (a +b) (3b + 7b) + 9(b² - a²) is b(12b + 7a)

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