Math, asked by yash9034, 4 months ago

a-[2ab-{3a-(2b-3c)}]

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Answered by Anonymous

15

$\boxed{ \huge{ \fcolorbox{yellow}{white}{ \pink{☆Solution}}} }$

$= > a-[2ab-{3a-(2b-3c)}]$

$= > a-[2ab-{3a-2b + 3c}]$

$= > a - 2ab + 3a + 2b - 3c$

$= > a + 3a - 2ab + 2b - 3c \\ = 4a - 2ab + 2b - 3c.$

Answered by deepshikha1335

0

i hope you understand it.

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