Question

a^2b^2-a^2-b^2+1 factorize ​

Answer 1

Required Answer:-

Given to factorise:

• a²b² - a² - b² + 1

Solution:

The given problem can be solved by grouping and using this identity,

★ a² - b² = (a + b)(a - b)

Let's solve it.

a²b² - a² - b² + 1

= a²(b² - 1) - 1(b² - 1) [Taking a² and -1 as common]

= (b² - 1)(a² - 1) [Taking b² - 1 as common]

Now, write the expression as a difference of two squares.

= [(b)² - (1)²][(a)² - (1)²]

Apply the identity,

= (b + 1)(b - 1)(a + 1)(a - 1)

Hence, the factorised form of the given polynomial is (b + 1)(b - 1)(a + 1)(a - 1)

Answer:

• The factorised form of the given polynomial is (b + 1)(b - 1)(a + 1)(a - 1)

Answer 2

Answer:

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