(a/2b+2b/a)^2-(2b/a-a/2b)^2
Answers
Answered by
14
Answer:
4
Step-by-step explanation:
(a/2b+2b/a)^2-(2b/a-a/2b)^2=[(a/2b)^2+(2b/a)^2+2]-[(a/2b)^2+(2b/a)^2-2]
=4
Answered by
7
Step-by-step explanation:
(a/2b + 2b/a)² - (2b/a - a/2b)²
It is in formulae...
write the identities of both :-
= (a²+ 2ab +b²) - (a²+ 2ab -b²)
= [(a/2b)² + 2× (a/2b)× (2b/a) +(2b/a)²] - [(2b/a)² +2×(2b/a) ×(a/2b) - (a/2b)²]
= [(a²/4b²) + 2 + (4b²/a²)] - [(4b²/a²) +2 -(a²/4b²)
Therefore, after cancelling —
It gives out...
= 2+2
= 4 Answer.
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