Question

(a/2b+2b/a)^2-(a/2b-2b/a)^2-4

Answer 1

${( \frac{a}{2b} + \frac{2b}{a}) }^{2} - {( \frac{a}{2b} - \frac{2b}{a})}^{2} - 4 \\ = ( \frac{a}{2b} + \frac{2b}{a} + \frac{a}{2b} - \frac{2b}{a} )( \frac{a}{2b} + \frac{2b}{a} - \frac{a}{2b} + \frac{2b}{a} ) - 4 \\ = ( \frac{2a}{2b} )( \frac{4b}{a} ) - 4 \\ = 4 - 4 = 0$

Answer 2

Answer:

Step-by-step explanation:

We know that

(x+y)^2 -(x-y)^2 =4xy-----(1)

Here

x=a/2b,

y=2b/a

Then given problem can be written as

(x+y)^2-(x-y)^2-4

=4xy-4 [from(1)]

=4*a/2b *2b/a -4

=4-4

=0

pzzzz mark me as brainliest