Question

a^2b^2x^2-(a^2+b^2)x+1=0​

Answer 1

Step-by-step explanation:

we have , a²b² x² + b² x²+ b² x - a² x-1 =0

[ -1 x a² b² = -a²b² = -a² b² = -a² X b²]

= a² b² x² + b² x - a² x - 1 = 0

= b²x ( a² x + 1 ) -1 ( a² x -1 = 0 )

= ( a² x + 1 ) ( b² x - 1 ) = 0

= a² x + 1 = 0 or b² x - 1 = 0

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