Question

a^2b^2x^2+(b^2-a^2)x-1=0

Answer 1

Step-by-step explanation:

a2b2x2 + (b2 - a2) x 1 = 0

so now lets put the result aside,

so the equation we have is a2b2x2 + (b2 - a2)x - 1.

a2b2x2 + x(b2 - a2) - 1 (b2 - a2).

We will take out the comman terms and the equation will be like this,

a2x (b2x-1) + 1 (b2x-1)

(a2x+1) (b2x-1)

x=     -1/a2  , 1/b2.

We have taken out the value of X which can be further used to solve the equation.

NOTE : The Answer or the result of the equation should be 0, If not then your output is incorrect).

Hope it helps.

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