Question

a^2b^2x^2 + b^2x - a^2x - 1

Answer 1

Answer:

x = ( -1 ) / a²    x = 1 / b²

Step-by-step explanation:

we have ,

a²b²x² + b²x - a²x - 1 = 0

from 1st and second terms take out "b²x" as common

b²x( a²x + 1 ) - 1 ( a²x - 1 ) = 0

by taking ( a²x + 1 ) as common from 2 terms we get

( b²x - 1 ) ( a²x + 1 ) = 0

either      ( a²x + 1 ) = 0

                 a²x = - 1

                   x = ( -1 ) / a²

or           ( b²x - 1 ) = 0

                    b²x = 1

                      x = 1 / b²

so the roots of the given equation are

 x = ( -1 ) / a² , 1 / b²

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