Math, asked by topper239, 9 months ago

(a - 2b) ^3 + (2b - 3c)^3 + (3c - a) ^3​

Answers

Answered by MayurShirsath
3

Answer:

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Answered by Fadhilla
0

Step-by-step explanation:

(a - 2b) ^3 + (2b - 3c)^3 + (3c - a) ^3

= a^3 - 2b^3 + 2b^3 - 3c^3 + 3c^3 - a^3

= a^3 - a^3 - 2b^3 + 2b^3 - 3c^3 + 3c^3

= 0

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