Question

a+2b+3c=0, show that a^3+8b^3+27c^3= 18abc

Answer 1

Heres your answer

According question

$a + 2b + 3c = 0 \\ \\ {a}^{3} + {8b}^{3} + {27c}^{3} = 18abc \\ \\ ( {a}^{3} + {2b}^{3} + {3c}^{3} ) = 3 \times 2b \times 3c \times c$
Hope it Helps!!