(a-2b-3c)^2 use identities
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Answer:
(a-2b-3c)²=a²+4b²+9c²-4ab+12bc-6ca
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Answer:
by using identity
(a-b-c)*2=a*2+b*2+c*2-2(ab-bc-ca)
=a*2+(-2b)*2+(-3c)*2+2×a×(-2b)+2×(-2b)×(-3c)+2×(-3c)×a
=a*2+4b*2+9c*2-4ab+12bc-6ac
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