Math, asked by bhargav3941, 8 months ago

(a-2b-3c)^2 use identities​

Answers

Answered by Tamilneyan
1

Answer:

(a-2b-3c)²=a²+4b²+9c²-4ab+12bc-6ca

Step-by-step explanation:

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Answered by pushpa1275
2

Answer:

by using identity

(a-b-c)*2=a*2+b*2+c*2-2(ab-bc-ca)

=a*2+(-2b)*2+(-3c)*2+2×a×(-2b)+2×(-2b)×(-3c)+2×(-3c)×a

=a*2+4b*2+9c*2-4ab+12bc-6ac

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