Question

(a, + 2b + 4c ) whole square

Answer 1

Answer:

$(a + 2b + 4c)^{2}$=

${a}^{2} + 4 {b}^{2} + 16 {c}^{2} + 4ab + 16bc + 8ac$

Answer 2

Answer:

a^2 + 4b^2+16^c^2+4ab + 16bc + 8 ca [ans]

Step-by-step explanation:

Hope it helps you.