Math, asked by abdulahadquadri03, 9 months ago

a+2b+c=0
Prove that a3+8b3+c3=6abc

Answers

Answered by srikanthn711
4

Answer:

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Step-by-step explanation:

a + 2b + c = 0 ( Given )

a + 2b = - c

on cubing both sides !!

( a + 2b )3 = ( - c )3

a3 + 8b3 + 3 a×2b (a +2b ) = - c3

a3 + 8b3 + 6ab (a + 2b ) = - c3

As we know a + 2b = - c

so

a3 + 8b3 + 6ab (- c) = - c3

a3 + 8b3 +c3 -6abc = 0

a3 + 8b3 + c3 = 6abc

Proved !!

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Answered by BrainlyIAS
2

Step-by-step explanation:

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