a+2b+c=0
Prove that a3+8b3+c3=6abc
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Step-by-step explanation:
a + 2b + c = 0 ( Given )
a + 2b = - c
on cubing both sides !!
( a + 2b )3 = ( - c )3
a3 + 8b3 + 3 a×2b (a +2b ) = - c3
a3 + 8b3 + 6ab (a + 2b ) = - c3
As we know a + 2b = - c
so
a3 + 8b3 + 6ab (- c) = - c3
a3 + 8b3 +c3 -6abc = 0
a3 + 8b3 + c3 = 6abc
Proved !!
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