{A+2d=15} x {2a+2d=25}. =?
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S10=10÷2 (2a +(10-1)d=5 (2a+9d)
125=5 (2a+9d)
125÷5=2a+9d
25=2a+9d _(1)
a3=a+2d
15=a+2d _(2)
subtracting equation (2) from (1) ,we get
2a+9d -a -2d =25-15
a+7d=10
a=10-7d _(3)
put the value of a in equation (2)
15=10-7d +2d
d=-1
put d=-1 in (3)
a=10-(-1×7)
a=17
now, a10=a+9d
a10=17-9
a10=8
Answered by
1
Answer:
S10=10÷2 (2a +(10-1)d=5 (2a+9d)
125=5 (2a+9d)
125÷5=2a+9d
25=2a+9d _(1)
a3=a+2d
15=a+2d _(2)
subtracting equation (2) from (1) ,we get
2a+9d -a -2d =25-15
a+7d=10
a=10-7d _(3)
put the value of a in equation (2)
15=10-7d +2d
d=-1
put d=-1 in (3)
a=10-(-1×7)
a=17
now, a10=a+9d
a10=17-9
a10=8
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