a 2digit no. is 3 more than 4times the sum of its digits.If 18 is added to the no. the digits are reversed. FIND THE NO.(number)?
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Step-by-step explanation:
so let the two digit number be 10x+y
where digit at ones pace is y and that of tens is x
according to first criterion,,
10x+y=3+4(x+y)
ie 10x+y=3+4x+4y
ie 6x-3y=3
so dividing by 3 on both sides,we get,
2x-y=1
hence y=2x-1 (1)
according to second case
10x+y+18=10y+x
so 9x-9y=-18
ie dividing by 9 on both sides we get
x-y=-2
so substitute value of y from (1)
we get
x-(2x-1)=-2
ie x-2x+1=-2
so -x=--3
so x=3
substitute value of x in any of two equations
we get,,y=5
so our assumed two digit number was 10x+y
=(10×3)+5
=30+5
=35
hence required two digit number is 35
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