Question

a 2digit number whose sum of digits is equal to 1/3 of number. what is the number​

Answer 1

Answer :

27

Solution :

Let x and y be the tens digit and unit digit of the required number respectively .

Then ,

Required number = 10x + y

Also ,

Sum of digits = x + y

Now ,

According to the question , the sum of digits is equal to the ⅓ rd of the required number .

Thus ,

=> Sum of digits = ⅓ rd of Required number

=> x + y = ⅓ × (10x + y)

=> 3(x + y) = 10x + y

=> 3x + 3y = 10x + y

=> 3y - y = 10x - 3x

=> 2y = 7x

=> y = 7x/2

• For x = 2 , then y = 7•2/2 = 7

Hence , Number = 27

• For others values of x , the given condition will not be satisfied to get a two digit number .

Hence ,

Required number = 27 .