A 2dm tube contains sugar solution mafe by dissolving 15 g of sugar in 100 cc of water. What is the angle of rotation of the plane of vibration of plane polarized light passing through tube if the specific rotation of sugar is 66.5?
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Explanation:
The formula of specific rotation is given by:
Specific rotation = alpha / C(g/ml) *L(dm)
Length of the tube = 20cm = 2 dm
Concentration (g/ml) of sugar solution = 15% = 15g sugar per 100 ml water
= 15g/100ml = 0.15 g /ml
Plane polarized light is rotated by 21 degree
Specific rotation = 21/ (2*0.15)
= 21/ 0.3 = 70 degree
Hence, specific rotation of sugar solution is 70 degre
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