Question

A 2g bullet is fired from a 800g pistol with speed of 50 ms. What is the
speed of the recoil of the pistol.
Solution:​

Answer 1

Answer:

Given:-

Mass (M1) = 2g = 0.002kg

Initial velocity (u1) = 50m/s

Final velocity (v1) = 0

Mass (M2) = 800g = 0.8kg

Initial velocity (u2) = 0

Final velocity (v2) = ?

By applying, Law of conservation of momentum

M1U1+M2U2 = M1V1+M2V2

0.002×50+0.8×0 = 0.002×0+0.8×v2

0.1 = 0.8v2

v2 = 0.1/0.8

= 0.125m/s.