Question

A 2g sample of xenon reacts eith flourine the mass of the compound produced is 3.158 g the empirical formula of the compound is [Xe-132 , f- 19 ] (1) Xef2 (2) Xef4 (3) Xef5 (4) Xef6 What is the answer and explain?

Answer 1

The question can be solved by long detqiled process, but if u want u can solve it like this too,
First calculate the mass of fluorine: 3.158-2 =1.158
Then check every option by seeing that 2 g Xe reacts with how much fluorine, like in first option, 132 g Xe reacts with 38 g fluorine then with 2 g Xe, the amount of fluorine that will react will be:- 2*38/132= 0.287g, which is not equal to 1.158 g (amount of fluorine reacted with 2g Xe)
According to this second option wiil givr the most accurate answer....
Hope it will help....

Answer 2

Answer:

First calculate the mass of fluorine: 3.158-2 =1.158

Then check every option by seeing that 2 g Xe reacts with how much fluorine, like in first option, 132 g Xe reacts with 38 g fluorine then with 2 g Xe, the amount of fluorine that will react will be:- 2*38/132= 0.287g, which is not equal to 1.158 g (amount of fluorine reacted with 2g Xe)

According to this second option wiil givr the most accurate answer....

Hope it will help....

Explanation: