A 2g sample of xenon reacts eith flourine the mass of the compound produced is 3.158g the empirical formula of the compound is
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It will form xenon difluoride . The empirical formula is Xe2F4
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Answer:
First calculate the mass of fluorine: 3.158-2 =1.158
Then check every option by seeing that 2 g Xe reacts with how much fluorine, like in first option, 132 g Xe reacts with 38 g fluorine then with 2 g Xe, the amount of fluorine that will react will be:- 2*38/132= 0.287g, which is not equal to 1.158 g (amount of fluorine reacted with 2g Xe)
Explanation:
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