Question

A 2g sample of xenon reacts with fluorine the mass of compound produced is 3.158g the empirical formula of the compound is?

Answer 1

Answer:

it's XeF4

Explanation:

First calculate the mass of fluorine: 3.158-2 =1.158

Then check every option by seeing that 2 g Xe reacts with how much fluorine, like in first option, 132 g Xe reacts with 38 g fluorine then with 2 g Xe, the amount of fluorine that will react will be:- 2*38/132= 0.287g, which is not equal to 1.158 g (amount of fluorine reacted with 2 g of Xe)

MARK THIS ANSWER BRAINLIEST

Answer 2

Answer:

First calculate the mass of fluorine: 3.158-2 =1.158

Then check every option by seeing that 2 g Xe reacts with how much fluorine, like in first option, 132 g Xe reacts with 38 g fluorine then with 2 g Xe, the amount of fluorine that will react will be:- 2*38/132= 0.287g, which is not equal to 1.158 g (amount of fluorine reacted with 2g Xe)

According to this second option wiil givr the most accurate answer....

Hope it will help....

Explanation: