Question

A=2i+j, b=3j-k and c =6i-2k then value of a-2b+3c would be

Answer 1

Solution :

Given,

a = 2i + j, b = 3j - k and c = 6i - 2k

Now, a - 2b + 3c

    = (2i + j) - 2 (3j - k) + 3 (6i - 2k)

    = 2i + j - 6j + 2k + 18i - 6k

    = (2 + 18) i + (1 - 6) j + (2 - 6) k

    = 20i - 5j - 4k

Note : Remember that i, j, k are normal unit vectors along x, y, z axes respectively and there is a cap sign (^) on each vector.

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