Question

A= 2i + j B=3j-k and C= 6i-2k value of A - 2B + 3C would be

Answer 1

A - 2B +3c
=(2i+j)-2(3j-k)+3(6i-2k)
=2i+j-6j-2k+18i-6k
=2i+18i+j-6j-2k-6k
=20i+(-5j)-8k
=20i-5j-8k.......ans

Answer 2

Given,

Vectors:

$A = 2i + j,$

$B = 3j-k,$ and

$C = 6i-2k.$

To find,

Value of A - 2B + 3C.

Solution,

Here, it can be seen that the three vectors A, B, and C are given, and it is required to find

A - 2B + 3C     ...(1)

So, to find the required value, we can simply substitute the values of A, B, and C in the above equation (1), and then simplify. Thus,

$A - 2B + 3C$

$= (2i + j) - 2(3j - k) + 3(6i - 2k)$

$= 2i + j - 6j + 2k + 18i - 6k$

$= 20i - 5j - 4k$

⇒ A - 2B + 3C = 20i - 5j - 4k.

Therefore, the value of A - 2B + 3C for the given vectors will be 20i - 5j - 4k.