Physics, asked by Everythingpurple, 8 months ago

A=2i+j
B=3j-k
C=6i-2k
Find value of A-2B+3C

Answers

Answered by kingsleychellakkumar

3

Answer:

20i-5j-4k

Explanation:

A-2B+3C = (2i+j) -2(3j-k) +3(6i-2k)

=2i+j-6j+2k+18i-6k

=20i-5j-4k

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Answered by georgerahul24

0

Answer:

Explanation:

A+3C=2i +j + 3(6i-2k) = 2i + j + 18i - 6k = 20i + j - 6k

A+3C-2B= 20i + j - 6k - 2(3j-k) = 20i + j - 6k -6j + 2k = 20i -5j -4k

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