A 2kg accelerate at the rate of 11m/s2 in a direction 30° north of east as shown in the figure. One force has a magnitude 11N and is directed north. The magnitude of second force is
1)11N 2)11√2N 3)11√3N 4)122N
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Answer:
Option (2)11√2 is the correct answer
Explanation:
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Concept:
- Calculating resultant vectors
- Force and acceleration
Given:
- Mass of object = 2kg
- acceleration of 11 m/s^2 30° north of east
- Vertical force F1 = 11 N
- The angle between horizontal force F2 and acceleration = 30°
- The angle between vertical force F1 and acceleration = 60°
Find:
- The magnitude of second force F2
Solution:
We know that F = ma
The net force causing acceleration of 11 m/s^2 = 2*11 = 22N
We know F1 = 11N
The resultant force of 2 perpendicular forces is the square root of the sum of the squares of the forces
22 = √11²+ F2²
22² = 121 + F2²
484 = 121+ F2²
363 = F2²
F2 = 11√3 N
The magnitude of the second force is 11√3 N.
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