Question

A 2kg ball drops vertically onto the floor with a speed of 25m/s and rebounds with a speed of 10m/s. What is the magnitude of impulse on the ball in kg.m/s

Answer 1

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Answer 2

Explanation:

Given that,

Mass of the ball, m = 2 kg

Initial speed of the ball, u = 25 m/s

Final speed of the ball, v = -10 m/s (as it rebounds)

We need to find the magnitude of Impulse on the ball. It is equal to the change in momentum of the ball i.e.

J = m × (v-u)

$J=2\times (-10-25)$

J = -70 kg m/s

So, the magnitude of Impulse on the ball is (-70 kg m/s). Hence, this is the required solution.