Question

A 2kg block drops vertically from a height of 40 cm on a spring whose force constant k is 1960 N/m then maximum compression of spring is. please fast​

Answer 1

Given data,

Mass of the body is ( m ) =2Kg

spring's constant (K)=1960N/m

height of the body =0.4m

Let the maximum distance spring will compressed =xm

initial potential energy of body =mg(h+x)

final potential energy = spring potential energy =21Kx2

according to the law of conservation of energy,

initial potential energy = final potential energy

 mg(h+x)=1/2 Kx2

2mgh+2mgx=Kx2

Kx2−2mgx−2mgh=0

⇒1960x2−2×2×9.8×x−2×2×9.8×0.4=0

⇒1960x2−39.2x−15.68=0

after solving this quadratic equations , we get x=0.1m

hence, answer is x=0.1m

Mark brainliest!!✔✔