A 2kg block slides on a horizontal floor with a speed of 4m/s . it strikes a uncompressed spring and compresses it till the block is motionless . the kinetic friction force is 15N and the spring constant is 10000N/m. The spring compresses by [AIEEE 2007]
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Answer:
I'll only tell the equation, you may please solve it ahead to get the final answer.
By work energy theorem, initial kinetic energy
= Energy dissipated in friction + Elastic potential energy in the spring
Let the compression be x
So, we can write
1/2mv^2 = fx + 1/2kx^2
Just put in all the values, aa everything is given
Put m=2
v=4
f=15
k=10000
Hope this helps you !
Solve the quadratic equation to get the final compression.
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