Question

A 2kg body is allowed to roll down,incline plane 4m 30°,calculate the work done,take g =10m​

Answer 1

Answer:

m= 2 kg

angle=60°

g=10m/s^2

h=4m

W=F.S.costheta

=mgh.cos theta

=2*10*4*cos60° (cos 60°=1/2)

=80*1/2

W=40J

it is possible only when height is given if the given displacement is height of the object from ground not displacement of the object

Answer 2

The work done by the body is 39.2 J.

Step-by-step explanation:

Mass of the body is 2 kg

It is rolled down from an inclined plane at an angle of 30 degrees from a height of 4 m. It is required to find the work done by the body.

The angle between the force and displacement will be = 90 - 30 = 60 degrees.

The work done by the body is given by :

$W=Fd\ \cos\theta\\\\W=2\times 9.8\times 4\times\cos(60)\\\\W=39.2\ J$

So, the work done by the body is 39.2 J.

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