A 2kg body is projected at 60 degree with 10m/s .At highest point its K.E will be
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Answer:
f=ma =2×-10=-20N
s=v^-u^2/2a
=0-100/2×-10
=5m
w =ek=fs ×cos theta
-20×5×cos60
-100×1/2
=-50j
as energy cant be negetive it is 50j
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