a 2kg body suspended from a spring of negligible mass is found to streach the spring by 0.1 m if the body is pulled down and the released what is the frequency of the oscillation
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Answer:
From formula 1, we can say
T=2πkM ...(1)
Also,
35T=2πkM+m ...(2)
Dividing eqn 2 and 1, we get
35=MM+m
∴925=MM+m
∴925=1+Mm
Hence, answer=16/9, i.e. option B
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