A 2kg cart moving right st 5 m/s on a frictionless track collides with a 3 kg cart moving left at 3m/s. Class 9.
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Answer:
mass(1) = 2kg
velocity (1) = 5m/s
KE = ½mv²
= ½2×5²
= 25J
mass(2) = 3kg
velocity (2) = 3m/s
KE = ½mv²
= 27/2
= 13.5 J
therefore, after the collision , the second cart will move back , while the first cart will remain in its motion with its KE = 11.5J
therefore, the velocity of the first cart changes to =>(½mv²) = 11.5
=> 2(v²) = 23
=> v² = 11.5
=> v = √11.5
=> v = 3.39 or 3.4m/s
hope it helped :)
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