Question

A 2Kg lump of cast iron at 90 O C is put into a plastic bucket containing

20 Kg of water at 20 O C. What is the final temperature of the water and

iron assuming no heat lost to the environment? Specific Heat Capacity

of water = 4200J/KgK, Specific Heat Capacity of cast iron=500J/KgK​

Answer 1

Explanation:

Given A 2 Kg lump of cast iron at 90 O C is put into a plastic bucket containing 20 Kg of water at 20 O C. What is the final temperature of the water and iron assuming no heat lost to the environment?  

• Let theta be the final temperature of the mixture.
• So heat energy lost by iron = heat energy gained by water.
•                       2 x 500 x (90 – theta) = 10 x 4200 x (theta – 20)
• Therefore 1000 (90 – theta) = 42000 (theta – 20)
•                90,000 – 1000 theta = 42,000 theta – 840000
•                90,000 + 8,40,000 = 42,000 theta + 1000 theta
•                    9,30,000 = 42,000 theta
•                      Or theta = 9,30,000 / 42,000
•                      Or theta = 22.14 degree C

Reference link will be

https://brainly.in/question/16868917