Physics, asked by kuchupudigowhar, 4 months ago

a 2kg mass moving with a velocity of 10 m/s collides with an another 6 kg mass moving in opposite direction with a velocity of 20 m/s. During the collision,they stick together Find their common velocity and momentum. A)12.5 m/s,100kgm/s B)12.5 m/s,50 kgm/s C)7.5 m/s,100kgm/s D)7.5 m/s,50 kgm/s


pls give step by step explanation solution. Thank you

Answers

Answered by ITZURADITYAKING
0

Answer:

A

Athey travel with a velocity of 5ms−1 in the same direction

Athey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,

Athey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)v

Athey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)v10=4v⇒v=5m/s

Answered by gs7729590
0

Answer:

Athey travel with a velocity of 5ms−1 in the same direction

Athey travel with a velocity of 5ms−1 in the same directionAthey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,

Athey travel with a velocity of 5ms−1 in the same directionAthey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,Athey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)v

Athey travel with a velocity of 5ms−1 in the same directionAthey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,Athey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)vAthey travel with a velocity of 5ms−1 in the same directionUsing momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)v10=4v⇒v=5m/s

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