Question

A 2kg object Is allowed to fall freely at t=0s.callculate its momentum at(a) t=1s,(b)t=1# and (c) t=2s during its free fall

Answer 1

using v= u+ at

a) v= -9.8 x 1s i.e. 9.8m/s hence, P= 1kg x 9.8 i.e. 9.8kgm/s

b) not clear in ur question

c)v= -9.8 x 2s i.e. 19.6 m/s hence, P= 1kg x 19.6m/si.e. 39.2kgm/s

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