A 2kg shot is fired from a canon of mass 200kg with a velocity of 50ms with respect to gun. What's the recoil velocity of gun?
Answers
Answered by
3
Answer:
25.25j
Explanation:
m1=2kg
m2=198kg
v2=50m/s
v1=?
since m1*v1=m2*v2
198*v2=2*50
198*v2=100
v2=100/198m/s
KE=1/2*mass of canon*(velocity of canon)^2
=1/2*198*100/198*100/198
=25.25252525J
which is approximately 25.25
please mark Brainly
Similar questions