Question

A 2kg shot is fired from a canon of mass 200kg with a velocity of 50ms with respect to gun. What's the recoil velocity of gun?

Answer 1

Answer:

25.25j

Explanation:

m1=2kg

m2=198kg

v2=50m/s

v1=?

since m1*v1=m2*v2

        198*v2=2*50

        198*v2=100

               v2=100/198m/s

KE=1/2*mass of canon*(velocity of canon)^2

   =1/2*198*100/198*100/198

   =25.25252525J

which is approximately 25.25

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