Question

A 2kg stone swung in a vertical circle by attaching it at the end of a string of length 2m . If the string can withstand a tension 140.6N, the maximum speed with which the stone can be rotated
Pls send me fast. I'm in need for it very badly!!!

Answer 1

Maximum speed, v = 11 m/s

Explanation:

Mass of the stone, m = 2 kg

Length of the string, l = 2 m

Tension in the string, T = 140.6 N

At maximum tension, the net force acting on it is given by :

$T-mg=\dfrac{mv^2}{r}$

$v=\sqrt{\dfrac{r(T-mg)}{m}}$

$v=\sqrt{\dfrac{2\times (140.6-2\times 9.8)}{2}}$

v = 11 m/s

So, the maximum speed with which the stone can be rotated is 11 m/s.

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Topic : Centripetal force

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