A 2kW kettle containing boiling water is placed on a balance. It is left there and continues to boil for 5 minutes. The balance reading changes by 0.2kg. What does this information give as a value for the specific latent heat of vaporisation of water
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Solution:
Assuming 100% of the heater's rating is transferred to the kettle:
2000 watts = 2000 J/s
after 5 mins = 300 s the amount of joules of heat transferred = 6E5 J
the amount of water converted to steam = 0.2 kg
so the heat of vaporization = 6E5/0.2 = 30E5 = 3E6 J/kg )
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sorry I don't know .....
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