Question

A 2m wire carrying a current 2A is oriented parallel to a magnetic field of 2T. The magnitude of the force it experiences is..​

Answer 1

Given:

A 2m wire carrying a current 2A is oriented parallel to a magnetic field of 2T.

To find:

Magnitude of force ?

Calculation:

General expression of force experienced by a wire in magnetic field is :

$\boxed{ \vec{F} = i( \vec{L} \times \vec{B})}$

$\implies | \vec{F}| = iLB \times \sin( \theta)$

• $\theta$ = 0° , because L and B vectors are parallel.

$\implies | \vec{F}| = 2 \times 2 \times 2 \times \sin( {0}^{ \circ} )$

$\implies | \vec{F}| = 8\times 0$

$\implies | \vec{F}| =0 \: N$

So, force experienced by wire is 0 Newton.