Question

a^2n–3 x (a)^n +1 /(a⁴)^-3 = (a³)³ ÷ (a⁶)^-3​

Answer 1

Step-by-step explanation:

${a}^{2n} - 3 {a}^{n} + \frac{1}{ {( {a}^{4} )}^{ - 3} } = \frac{{ ({a}^{3}) }^{3} }{ { ({a}^{6}) }^{ - 3} } \\ {a}^{2n} - 3 {a}^{n} + \frac{1}{ {a}^{ - 12} } = \frac{{ a }^{9} }{ { a }^{ - 18} } \\ {a}^{2n} - 3 {a}^{n} + {a}^{12} = {a}^{9 - ( - 18)} \\ {a}^{2n} - 3 {a}^{n} + {a}^{12} = {a}^{27} \\ {a}^{2n} - 3 {a}^{n} = {a}^{27} - {a}^{12} \\ {a}^{n} ( {a}^{n} - 3) = {a}^{12} ( {a}^{15} - 1) \\ compaire : \\ n = 12$

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