Question

A 2uc charge is moved along an equipotential surface having a potential of -4 volt the work done is​

Answer 1

Given:-

• Charge ,Q = 2µC

• Potential Difference ,V = -4 v

To Find:-

• Work done ,W

Solution:-

As we know that potential difference is also defined as the work done by charge .

Now, Converting the Unit here

1µC (microcoulomb) = 10^-6 C

Therefore, 2 µC = 2× 10^-6 C

• V = W/Q

Where,

V is the potential difference

W is the Work Done

Q is the Charge.

Substitute the value we get

➨ -4 = W/2×10^-6

➨ W = -4×2 × 10^-6

➨ W = -8 × 10^-6 J

Therefore, the Work Done is -8 × 10^-6 Joules.

Answer 2

$\large{\boxed{\boxed{\textsf {Let's \: Understand \: Question \: F1}^{\textsf{st}}}}}$

Here, we have given that 2µC of charge is moving along an equipotential surface which have potential diff. of -4 volt and we have to calculate the work done by it.

$\large{\boxed{\boxed{\textsf {How To Do It?}}}}$

In this question f1st we change the unit of charge from microcoulomb to Coulomb. The simply using the formula (V = w/q) then substituting values into it and hence we will got our required answer.

Let's Do It ⚡

$\huge{\underline{\boxed{\textsf {AnSwer}}}}$

___________________________

Given:

◗Charge = 2µC

◗Potential Difference = -4V

Find:

◖Work Done by it.

Solution:

Here, we have 2µC of charge

we, know that 1µC = $\bf{10^{-6} C}$

So, 2µC = $\bf{2\times 10^{-6}}$

Now, using

$\begin{lgathered}\underline{\boxed{\sf V = \dfrac{w}{q}}} \\ \end{lgathered}$

$\begin{lgathered} \sf where \small{\begin{cases} \sf V = -4 \\ \sf q = 2\times 10^{-6} \end{cases}} \end{lgathered}$

$\pink\bigstar$ Substituting these values:

$\begin{lgathered} \dashrightarrow\sf V = \dfrac{w}{q}\\ \\ \end{lgathered}$

$\begin{lgathered} \dashrightarrow\sf - 4= \dfrac{w}{2 \times {10}^{ - 6} }\\ \\ \end{lgathered}$

$\begin{lgathered} \dashrightarrow\sf -4\times 2 \times {10}^{ - 6} = w\\ \\ \end{lgathered}$

$\begin{lgathered} \dashrightarrow\sf -8 \times {10}^{ - 6} = w\\ \\ \end{lgathered}$

$\begin{lgathered}\underline{\boxed{\sf \therefore Work\:done\:is\:-8\times 10^{-6}}} \\ \end{lgathered}$