Question

a^2x^2+(a^2+b^2)x+b^2=0​

Answer 1

Answer:

a²x²+(a²+b²)x+b²=0

a²x² +a²x +b²x + a²b² + b⁴=0

a²x(x+1) +b²(x+a²+b²)=0

a²x+b²=o...1 x+1=0 ...2 x+a²+b²=0....3

put the value x= -1 put the value. of x

of x

a²(-1)+b²=0 -1+a²+b²=0

-a²+b²=0 a²+b²=1

b²=a².....4 put the value of b²=a²

a²+a²=1

2a²=1

therefore a²=1/2

b²=1/2

bcoz a²=1/2