Question

A(3,0)and B(-3,0) are two fixed points. find the locus of a moving point P such that PA is perpendicular to P B​

Answer 1

Answer:

${x}^{2} + {y}^{2} = 9$

Step-by-step explanation:

let the co coordinate os P be (x,y)

given PA is perpendicular to PB

therefore the multiplication of their is equal to -1

$\frac{y}{x - 3} \times \frac{y}{x + 3} = - 1 \\ {y}^{2} = 9 - {x}^{2} \\ \\ {x}^{2} + {y}^{2} = 9$

Answer 2

Answer:

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Step-by-step explanation:

your answer