Math, asked by akshasen15, 6 months ago

A(-3,0) B(10-2) and C(12.3) are the vertices of AABC. Find the equation of the altitude through A and B.

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Answers

Answered by Anonymous
4

Answer:

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Step-by-step explanation:

SOLUTION

Equation of altitude through A

The altitude passing through the vertex A intersect the side BC at D.

AD is perpendicular to BC.

Slope of BC = (y2 - y1)/(x2 - x1)

= (3 - (-2))/(12 - 10)

= (3 + 2)/2

= 5/2

Equation of the altitude passing through the vertex A :

(y - y1) = (-1/m)(x - x1)

A(-3, 0) and m = 5/2

(y - 0) = -1/(5/2)(x - (-3))

y = (-2/5) (x + 3)

5y = -2x - 6

2x + 5y + 6 = 0  is the equation of altitude through A

Equation of altitude through B

Slope of AC = (y2 - y1)/(x2 - x1)

= (3 - 0)/(12 - (-3))

= 3/(12+3)

= 3/15

= 1/5

Equation of the altitude passing through the vertex B :

(y - y1) = (-1/m)(x - x1)

B(10, -2) and m = 1/5

(y - (-2)) = -1/(1/5)(x - 10)

y + 2 = -5(x - 10)

y + 2 = -5x + 50

5x + y + 2 - 50 = 0

5x + y - 48 = 0 is the equation of altitude through B

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