Physics, asked by sanginiagrawal21, 3 months ago

A 3.0 cm long wire carrying a current of 10A is placed perpendicular to a magnetic field of 0.27T. Find the force experienced by the wire.

Answers

Answered by amudhan159

1

Answer:

Explanation:

we know that the force on current carrying loop,F=BIL

B-magnetic field

I-current

L-length

therefore force experienced=0.27×10×3×10⁻² (;1m=100cm for 3 cm =3×10⁻²m)

=0.071 N

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