Question

a 3.0 kg fish is swimming at 1.5 m/s to the right. it swallows a 0.25 kg fish swimming to the left at 4.0 m/s. what is the speed and direction of the larger fish immediately after lunch? *

Answer 1

Explanation:

Given a 3.0 kg fish is swimming at 1.5 m/s to the right. it swallows a 0.25 kg fish swimming to the left at 4.0 m/s. what is the speed and direction of the larger fish immediately after lunch?  

• Mass of fish m1 = 3 kg
• Velocity v1 = 1.5 m/s
• Mass of small fish m2 = 0.25 kg
• Velocity v2 = - 4 m/s (negative sign since the direction is opposite)
• Therefore total mass of fish after swallowing will be M = 3 + 0.25 = 3.25 kg
• Let the final velocity of fish be V
• Now according to the law of conservation of momentum we have
•       So m1v1 + m2v2 = M x V
•             3 x 1.5 + 0.25 x – 4 = 3.25 x V
•                 4.5 – 1 = 3.25 V
•                     3.25 V = 3.5
•                       Or V = 1.076 m/s
• So speed of the fish will be 1.076 m/s

Reference link will be

https://brainly.in/question/6054948

Answer 2

Answer:

V=1.076m/s will be the correct answer