a 3.0 kg fish is swimming at 1.5 m/s to the right. it swallows a 0.25 kg fish swimming to the left at 4.0 m/s. what is the speed and direction of the larger fish immediately after lunch? *
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Explanation:
Given a 3.0 kg fish is swimming at 1.5 m/s to the right. it swallows a 0.25 kg fish swimming to the left at 4.0 m/s. what is the speed and direction of the larger fish immediately after lunch?
- Mass of fish m1 = 3 kg
- Velocity v1 = 1.5 m/s
- Mass of small fish m2 = 0.25 kg
- Velocity v2 = - 4 m/s (negative sign since the direction is opposite)
- Therefore total mass of fish after swallowing will be M = 3 + 0.25 = 3.25 kg
- Let the final velocity of fish be V
- Now according to the law of conservation of momentum we have
- So m1v1 + m2v2 = M x V
- 3 x 1.5 + 0.25 x – 4 = 3.25 x V
- 4.5 – 1 = 3.25 V
- 3.25 V = 3.5
- Or V = 1.076 m/s
- So speed of the fish will be 1.076 m/s
Reference link will be
https://brainly.in/question/6054948
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3
Answer:
V=1.076m/s will be the correct answer
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