A 3.0-kg object is initially at rest. It then receives an impulse of magnitude 15 N.S. After the impulse, the object has
(A) a speed of 45 m/s
(B) a momentum of magnitude 5.0 kg m/s (
C) a speed of 7.5 m/s
(D) a momentum of magnitude 15 kg m/s
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Given : A 3.0-kg object is initially at rest. It then receives an impulse of magnitude 15 N.s.
To Find : After the impulse, the object has
Solution:
p = change in momentum
Δv = change in velocity
m = mass of the object
Impulse = F Δ t
Δ p = FΔ t = mΔv
mΔv = 15
initial momentum was zero as at rest
Hence Momentum of magnitude 15 kg.m/s
mΔv = 15
m = 3 kg
=> 3Δv = 15
=> Δv = 5 m/s
Object has speed of 5 m/s
a momentum of magnitude 15 kg.m/s is the correct option
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