A 3.0-kg object is initially at rest. It then receives an impulse of magnitude 15 N.s. After the impulse, the object has (A) a speed of 45 m/s (B) a momentum of magnitude 5.0 kg.m/s (C) a speed of 7.5 m/s (D) a momentum of magnitude 15 kg.m/s
Answers
Given : A 3.0-kg object is initially at rest. It then receives an impulse of magnitude 15 N.s.
To Find : After the impulse, the object has
Solution:
p = change in momentum
Δv = change in velocity
m = mass of the object
Impulse = F Δ t
Δ p = FΔ t = mΔv
mΔv = 15
initial momentum was zero as at rest
Hence Momentum of magnitude 15 kg.m/s
mΔv = 15
m = 3 kg
=> 3Δv = 15
=> Δv = 5 m/s
Object has speed of 5 m/s
a momentum of magnitude 15 kg.m/s is the correct option
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Answer:
p = change in momentum
Av = change in velocity = FAt
m = mass of the object
Impulse A p = FA t = mAv
m*Delta * v = 15
initial momentum was zero as at rest Hence Momentum of magnitude 15 kg.m/s
m*Delta * v = 15
m = 3 kg
=> 3Δν = 15
=> Av = 5 m/s
Object has speed of 5 m/s
a momentum of magnitude 15 kg.m/s is
the correct option..