Math, asked by mayani, 7 months ago

a^3-1/a^3-2a+2/a
factorise this​

Answers

Answered by rajeevr06
2

Answer:

 {x}^{ 3}  -  \frac{1}{ {x}^{3} }  - 2x +  \frac{2}{x}  =

(x -  \frac{1}{x} )( {x}^{2}  + x \times  \frac{1}{x}  +  \frac{1}{ {x}^{2} } ) - 2(x -  \frac{1}{x} ) =

(x -  \frac{1}{x} )( {x}^{2}  + 1 +  \frac{1}{ {x}^{2} }  - 2) =

(x -  \frac{1}{x} )( {x}^{2}  +  \frac{1}{ {x}^{2} }  - 1)

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