Question

A) 3(+2)−2(−1)=7
B) 8(2−5)−6(3−7)=1
Find the variable

Answer 1

Let
2x+3y
1
​
=u and
3x−2y
1
​
=v. Then, the given system of equations becomes

2
1
​
u+
7
12
​
v=
2
1
​
⇒7u+24v=7 ..(i)

and, 7u+4v=2 .(ii)

Substracting equation (ii) from equation (i), we get

20v=5⇒v=
4
1
​


Putting v=
4
1
​
in equation (i), we get

7u+6=7⇒u=
7
1
​


Now, u=
7
1
​
⇒
2x+3y
1
​
=
7
1
​
⇒2x+3y=7 (iii)

and, u=
4
1
​
⇒
3x−2y
1
​
=
4
1
​
⇒3x−2y=4 .(iv)

Multiplying equation (iii) by 2 and equation (iv) by 3, we get
4x+6y=14 .(v)
9x−6y=12 .(vi)

Adding equations (v) and (vi), we get
13x=26⇒x=2

Putting x=2 in equation(v), we get
8+6y=14⇒y=1

Hence, x=2,y=1 is the solution of the given system of equations.

Answer 2

(a) 3×2-2×-1=7

=6-2=7

=4 is not equal to 7

So,LHS is not equal to RHS

(b) 8×2-5-6×3-7

=16-5-18-7

=11-11

=0

0 is not equal to 1

So, LHS is not equal to RHS

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